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Using “yield” to enumerate endless sequence
Craig Andera in his blog post showed yet another Fibonacci algorithm, this one with “yeild” operator. private IEnumerable Fibonacci() { yield return 0; yield return 1; int a = 0; int b = 1; while (true) { int temp = a + b; a = b; b = temp; yield return b; } } Now it's possible to fetch Fibonacci...
Posted to
Vagif Abilov's blog on .NET
by
Vagif Abilov
on Thu, Mar 11 2010
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